Write the Lewis dot structure of the $CO$ molecule.

(N/A) $(i)$ $C$ has electronic configuration $[He] 2s^2 2p^2$,so valence electrons $= 4$.
$O$ has electronic configuration $[He] 2s^2 2p^4$,so valence electrons $= 6$.
Therefore,total valence electrons in $CO = 4 + 6 = 10$.
$(ii)$ The skeletal structure of $CO$ is $C-O$.
$(iii)$ If we place a single bond between $C$ and $O$,the octet is not satisfied for $C$. By forming a triple bond between $C$ and $O$,we share $6$ electrons.
$(iv)$ The final Lewis structure is $:C \equiv O:$,where $C$ and $O$ both complete their octets through sharing $6$ electrons and having one lone pair each.