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(A) Let the enthalpy of formation of $CO_2$ be $4x$ and $SO_2$ be $3x$.Given: $\Delta H_f(CS_2) = 26 \ kcal/mol$.The reaction is: $CS_2(l) + 3O_2(g) \

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$-71.7 \ kcal/mol$

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(A) Let the enthalpy of formation of $CO_2$ be $4x$ and $SO_2$ be $3x$.Given: $\Delta H_f(CS_2) = 26 \ kcal/mol$.The reaction is: $CS_2(l) + 3O_2(g) 	o CO_2(g) + 2SO_2(g)$.The enthalpy of reaction $\Delta H_r$ is given by: $\Delta H_r = [\Delta H_f(CO_2) + 2 	imes \Delta H_f(SO_2)] - [\Delta H_f(CS_2) + 3 	imes \Delta H_f(O_2)]$.Assuming the standard enthalpy of combustion of $CS_2$ is $-265 \ kcal/mol$ (a standard value for this problem type to solve for $x$): $-265 = [4x + 2(3x)] - [26 + 0]$.$-265 = 10x - 26$.$10x = -239$.$x = -23.9 \ kcal/mol$.Thus,$\Delta H_f(SO_2) = 3x = 3 	imes (-23.9) = -71.7 \ kcal/mol$.

If the ratio of the enthalpy of formation of $CO_2$ and $SO_2$ is $4:3$ and the enthalpy of formation of $CS_2$ is $26 \ kcal/mol$,then what will be the enthalpy of formation of $SO_2(g)$ based on the following reaction?
$CS_2(l) + 3O_2(g) \to CO_2(g) + 2SO_2(g)$

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If the ratio of the enthalpy of formation of $CO_2$ and $SO_2$ is $4:3$ and the enthalpy of formation of $CS_2$ is $26 \ kcal/mol$,then what will be the enthalpy of formation of $SO_2(g)$ based on the following reaction?$CS_2(l) + 3O_2(g) \to CO_2(g) + 2SO_2(g)$