For the reaction 2SO_{2(g)} + O_{2(g)} rightl | vedclass

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Question

(C) Given the reaction: $2SO_{2(g)} + O_{2(g)} ightleftharpoons 2SO_{3(g)}$ with equilibrium constant $K_{c1} = 7 	imes 10^{25}$.For the target rea

Vedclass · Accepted Answer

$3.78 	imes 10^{-13}$

Vedclass · Answer

(C) Given the reaction: $2SO_{2(g)} + O_{2(g)} ightleftharpoons 2SO_{3(g)}$ with equilibrium constant $K_{c1} = 7 	imes 10^{25}$.For the target reaction: $SO_{3(g)} ightleftharpoons SO_{2(g)} + \frac{1}{2}O_{2(g)}$,we observe that the reaction is reversed and multiplied by a factor of $\frac{1}{2}$.Therefore,the new equilibrium constant $K_{c2}$ is given by $K_{c2} = (\frac{1}{K_{c1}})^{1/2}$.$K_{c2} = (\frac{1}{7 	imes 10^{25}})^{1/2} = \frac{1}{\sqrt{7} 	imes 10^{12.5}} = \frac{1}{2.6457 	imes 10^{12.5}} \approx 0.378 	imes 10^{-12.5} = 3.78 	imes 10^{-13}$.

For the reaction $2SO_{2(g)} + O_{2(g)} \rightleftharpoons 2SO_{3(g)}$ at $298 \ K$,the $K_c$ is $7 \times 10^{25}$. Calculate $K_c$ for the reaction $SO_{3(g)} \rightleftharpoons SO_{2(g)} + \frac{1}{2}O_{2(g)}$.

Similar Questions

For the following gaseous equilibria at $300 \ K$,find the increasing order of the ratio $\frac{K_p}{K_c}$ for $X, Y,$ and $Z$:
$X: 2SO_{2(g)} + O_{2(g)} \rightleftharpoons 2SO_{3(g)}$
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$Z: 2HI_{(g)} \rightleftharpoons H_{2(g)} + I_{2(g)}$

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What is the relationship between $K_{p}$ and $K_{c}$ when $\Delta n = 0$,$\Delta n > 0$,and $\Delta n < 0$?

The equilibrium constant $(K_P)$ for the reaction $2SO_2 + O_2 \rightleftharpoons 2SO_3$ at $1000 \ K$ is $3.5$. The partial pressure of oxygen gas to give equal mole of $SO_2$ and $SO_3$ is $... \ atm$.

For the reaction $2Ag_2O_{(s)} \rightleftharpoons 4Ag_{(s)} + O_{2(g)}$,the partial pressure of $O_2$ is given by:

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