$(i)$ Draw the gas phase and solid phase structure of $H_2O_2$.
$(ii)$ $H_2O_2$ is a better oxidizing agent than water. Explain.

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(N/A) $(i)$ $H_2O_2$ has a non-planar structure. The gas phase structure has a dihedral angle of $111.5^{\circ}$ and the solid phase structure has a dihedral angle of $90.2^{\circ}$.
$(ii)$ $H_2O_2$ is a better oxidizing agent than water because the $O-O$ bond in $H_2O_2$ is weak and can easily break to release oxygen atoms or accept electrons to form water.
Examples:
$1.$ $H_2O_2$ oxidizes an acidified solution of $KI$ to $I_2$,which gives a blue color with starch solution:
$2KI + H_2SO_4 + H_2O_2 \longrightarrow K_2SO_4 + 2H_2O + I_2$
$2.$ $H_2O_2$ oxidizes black $PbS$ to white $PbSO_4$:
$PbS + 4H_2O_2 \longrightarrow PbSO_4 + 4H_2O$

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Similar Questions

With reference to the redox properties of hydrogen peroxide $(H_2O_2)$,which of these reactions are feasible?
$(I)$ $2Fe^{2+} + 2H^{+} + H_2O_2 \longrightarrow 2Fe^{3+} + 2H_2O$
$(II)$ $2MnO_4^{-} + 6H^{+} + 5H_2O_2 \longrightarrow 2Mn^{2+} + 8H_2O + 5O_2$
$(III)$ $2Fe^{2+} + H_2O_2 \longrightarrow 2Fe^{3+} + 2OH^{-}$
$(IV)$ $2MnO_4^{-} + 3H_2O_2 \longrightarrow 2MnO_2 + 2H_2O + 3O_2 + 2OH^{-}$

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The species that does not contain peroxide ion is

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