Determine the structure and name of $A$ and $B$ in the following reaction sequence:
$(A)$ $\xrightarrow{NaOH, -H_2O} (B)$ $\xrightarrow{NaOH, CaO, \Delta} CH_3CH_3$

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The given reaction sequence is for the preparation of alkanes via decarboxylation.
Step $1$: Propanoic acid $(CH_3CH_2COOH)$ reacts with $NaOH$ to form sodium propanoate $(CH_3CH_2COONa)$ and water.
Thus,$(A) = CH_3CH_2COOH$ (Propanoic acid) and $(B) = CH_3CH_2COONa$ (Sodium propanoate).
Step $2$: Sodium propanoate undergoes decarboxylation with soda-lime $(NaOH + CaO)$ upon heating to yield ethane $(CH_3CH_3)$.

Explore More

Similar Questions

$R'-Cl \xrightarrow{Na/\text{Ether}} 2,3-\text{dimethylbutane}$. What is $R'$ in the above reaction?

The compound with molecular formula $C_{20}H_{42}$ is

The reaction $CH_4 + Cl_2 \xrightarrow{uv \ light} CH_3Cl + HCl$ is an example of

Which of the following is $NOT$ obtained when a mixture of methyl bromide and ethyl bromide is treated with sodium metal in the presence of dry ether?

Select the reaction$(s)$ that would result in the formation of $2-$bromopropane.
$(I) \ CH_3-CH=CH_2 + HBr \xrightarrow{\text{peroxide}}$
$(II) \ CH_3-CH=CH_2 + HBr \xrightarrow{CCl_4}$
$(III) \ CH_3-CH_2-CH_3 + Br_2 \xrightarrow{hv}$
$(IV) \ CH_3-CH=CH_2 + Br_2 \xrightarrow{CCl_4}$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo