Draw the resonance structures of $N_2O_4$,state its shape,and indicate the bond angles and bond lengths.

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(N/A) The $N_2O_4$ (dinitrogen tetroxide) molecule is planar with $D_{2h}$ symmetry.
Its resonance structures involve the delocalization of electrons across the $N-N$ bond and the $N-O$ bonds.
In the resonance hybrid,the $N-N$ bond length is approximately $1.75 \ \mathring{A}$,and the $N-O$ bond length is approximately $1.19 \ \mathring{A}$.
The bond angle $\angle O-N-O$ is approximately $135^{\circ}$ and $\angle N-N-O$ is approximately $112.5^{\circ}$.
The molecule is planar,meaning all atoms lie in the same plane.

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For which of the following can resonance structures be drawn? Why?
$CO_2, NO_2, O_3, O_2, CH_4$

Explain why the following two structures,$I$ and $II$,cannot be the major contributors to the real structure of $CH_{3}COOCH_{3}$.
$I: CH_{3}-C^{+}(O^{-})-OCH_{3}$
$II: CH_{3}-C(=O^{-})-OCH_{3}^{+}$

The stability order of the following resonance structures is:
$I. CH_2=CH-CH=O$
$II. CH_2^+-CH=CH-O^-$
$III. CH_2^--CH=CH-O^+$

In the anion $HCOO^-$,the two carbon-oxygen bonds are found to be of equal length. What is the reason for it?

Which of the following pairs does not represent resonating structures?

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