(B) The reaction between lead$(II)$ sulfide $(PbS)$ and ozone $(O_3)$ is an oxidation reaction. Ozone acts as a strong oxidizing agent. The balanced c

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(B) The reaction between lead$(II)$ sulfide $(PbS)$ and ozone $(O_3)$ is an oxidation reaction. Ozone acts as a strong oxidizing agent. The balanced chemical equation is: $PbS + 4O_3 \,\to PbSO_4 + 4O_2$ Therefore,the missing product is $PbSO_4$.

Class 11 Chemistry Redox Reactions Redox reaction and Method for balancing Redox reaction

Easy

$PbS + 4O_3 \,\to ?\,+\,4O_2$

A
$PbO$
B
$PbSO_4$
C
$PbO_2$
D
$PbS_2$

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Class 11 Questions

Class 11

Chemistry Questions

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Redox Reactions

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Redox reaction and Method for balancing Redox reaction

For the redox reaction $ xMnO_{4}^{-} + yH_{2}C_{2}O_{4} + zH^{+} \rightarrow mMn^{2+} + nCO_{2} + pH_{2}O $,the values of $ x, y, m $ and $ n $ are:

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When $KMnO_4$ reacts with $Br^-$ in a basic medium to give bromate ion,the oxidation state of $Mn$ changes from $7$ to . . . . . .

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Acidified potassium dichromate on reacting with a sulphite is reduced to

Medium

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Assign $A, B, C, D$ from the given type of reaction.
$2NaNO_3 \xrightarrow{\Delta} 2NaNO_2 + O_2$

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$2MnO_4^{-} + 5H_2O_2 + 6H^{+} \to 2Z + 5O_2 + 8H_2O$. In this reaction $Z$ is

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$PbS + 4O_3 \,\to ?\,+\,4O_2$

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For the redox reaction $ xMnO_{4}^{-} + yH_{2}C_{2}O_{4} + zH^{+} \rightarrow mMn^{2+} + nCO_{2} + pH_{2}O $,the values of $ x, y, m $ and $ n $ are:

When $KMnO_4$ reacts with $Br^-$ in a basic medium to give bromate ion,the oxidation state of $Mn$ changes from $7$ to . . . . . .

Acidified potassium dichromate on reacting with a sulphite is reduced to

Assign $A, B, C, D$ from the given type of reaction.$2NaNO_3 \xrightarrow{\Delta} 2NaNO_2 + O_2$

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Assign $A, B, C, D$ from the given type of reaction.
$2NaNO_3 \xrightarrow{\Delta} 2NaNO_2 + O_2$