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(D) The unit of force is $N$ (Newton),which is $kg\,m\,s^{-2}$.Given unit is $N\,m^{-1}\,s^{-2}$.Substituting the base units of force: $(kg\,m\,s^{-2}

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None of these

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(D) The unit of force is $N$ (Newton),which is $kg\,m\,s^{-2}$.Given unit is $N\,m^{-1}\,s^{-2}$.Substituting the base units of force: $(kg\,m\,s^{-2}) 	imes m^{-1} 	imes s^{-2} = kg\,s^{-4}$.Alternatively,let us check the dimensions: $[N] = [MLT^{-2}]$,$[m^{-1}] = [L^{-1}]$,$[s^{-2}] = [T^{-2}]$.Multiplying these: $[MLT^{-2}] 	imes [L^{-1}] 	imes [T^{-2}] = [MT^{-4}]$.This unit does not correspond to any standard fundamental physical quantity like pressure $(N\,m^{-2})$,surface tension $(N\,m^{-1})$,or force constant $(N\,m^{-1})$.Therefore,the correct option is $D$.

List-$I$	List-$II$
$(A)$ Young's Modulus	$(I)$ $[ML^{-1}T^{-1}]$
$(B)$ Torque	$(II)$ $[ML^{-1}T^{-2}]$
$(C)$ Coefficient of Viscosity	$(III)$ $[M^{-1}L^3T^{-2}]$
$(D)$ Gravitational Constant	$(IV)$ $[ML^2T^{-2}]$

Identify the physical quantity that has the unit $N\,m^{-1}\,s^{-2}$.

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Match List-$I$ with List-$II$:
List-$I$ List-$II$
$(A)$ Young's Modulus $(I)$ $[ML^{-1}T^{-1}]$
$(B)$ Torque $(II)$ $[ML^{-1}T^{-2}]$
$(C)$ Coefficient of Viscosity $(III)$ $[M^{-1}L^3T^{-2}]$
$(D)$ Gravitational Constant $(IV)$ $[ML^2T^{-2}]$

Choose the correct answer from the options given below:

Identify the pair whose dimensions are equal.

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