Match Column-I with Column-II. Column-I | vedclass

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(B) The resultant $R$ of two vectors $\vec{A}$ and $\vec{B}$ is given by $R = \sqrt{A^2 + B^2 + 2AB \cos 	heta}$,where $	heta$ is the angle between

Vedclass · Accepted Answer

$(1-c), (2-a)$

Vedclass · Answer

(B) The resultant $R$ of two vectors $\vec{A}$ and $\vec{B}$ is given by $R = \sqrt{A^2 + B^2 + 2AB \cos 	heta}$,where $	heta$ is the angle between them.For the resultant to be maximum,$\cos 	heta$ must be maximum,i.e.,$\cos 	heta = 1$,which implies $	heta = 0^o$. Thus,$(1-c)$.For the resultant to be minimum,$\cos 	heta$ must be minimum,i.e.,$\cos 	heta = -1$,which implies $	heta = 180^o$. Thus,$(2-a)$.Therefore,the correct matching is $(1-c), (2-a)$.

Column-$I$	Column-$II$
$(1)$ Resultant of two vectors is maximum	$(a)$ $180^o$
$(2)$ Resultant of two vectors is minimum	$(b)$ $90^o$
	$(c)$ $0^o$

Match Column-$I$ with Column-$II$.

Column-$I$ Column-$II$

$(1)$ Resultant of two vectors is maximum $(a)$ $180^o$

$(2)$ Resultant of two vectors is minimum $(b)$ $90^o$

$(c)$ $0^o$

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Match Column-$I$ with Column-$II$. Column-$I$ Column-$II$ $(1)$ Resultant of two vectors is maximum $(a)$ $180^o$ $(2)$ Resultant of two vectors is minimum $(b)$ $90^o$ $(c)$ $0^o$