(B) $KI$ reacts with concentrated $H_2SO_4$ to produce $HI$ and $KHSO_4$. $KI + H_2SO_4 \xrightarrow{\Delta} KHSO_4 + HI$ $HI$ is a strong reducing ag

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(B) $KI$ reacts with concentrated $H_2SO_4$ to produce $HI$ and $KHSO_4$. $KI + H_2SO_4 \xrightarrow{\Delta} KHSO_4 + HI$ $HI$ is a strong reducing agent,so it reduces $H_2SO_4$ to $SO_2$ and gets oxidized to $I_2$. $2HI + H_2SO_4 \to I_2 + SO_2 + 2H_2O$ Thus,the final product is $I_2$ (violet vapours).