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(B) The effective acceleration due to gravity $g'$ at a latitude $\lambda$ is given by $g' = g - \omega^2 R \cos^2 \lambda$,where $g$ is the accelerat

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It decreases the acceleration due to gravity at the equator.

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(B) The effective acceleration due to gravity $g'$ at a latitude $\lambda$ is given by $g' = g - \omega^2 R \cos^2 \lambda$,where $g$ is the acceleration due to gravity without rotation,$\omega$ is the angular velocity of the Earth,and $R$ is the radius of the Earth.Because of the term $\omega^2 R \cos^2 \lambda$,the rotation of the Earth causes a decrease in the effective acceleration due to gravity.This effect is zero at the poles (where $\lambda = 90^\circ$) and maximum at the equator (where $\lambda = 0^\circ$).

How does the rotation of the Earth affect the acceleration due to gravity on its surface?

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