Calculate the mass of oxygen present in 0.1 | vedclass

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(A) The chemical formula is $Na_2CO_3 \cdot 10H_2O$.In $1 \ mol$ of $Na_2CO_3 \cdot 10H_2O$,there are $3$ oxygen atoms in $Na_2CO_3$ and $10$ oxygen a

Vedclass · Accepted Answer

$20.8$

Vedclass · Answer

(A) The chemical formula is $Na_2CO_3 \cdot 10H_2O$.In $1 \ mol$ of $Na_2CO_3 \cdot 10H_2O$,there are $3$ oxygen atoms in $Na_2CO_3$ and $10$ oxygen atoms in $10H_2O$,totaling $13$ moles of oxygen atoms.For $0.1 \ mol$ of the compound,the moles of oxygen atoms = $0.1 	imes 13 = 1.3 \ mol$.The molar mass of oxygen is $16 \ g/mol$.Mass of oxygen = $1.3 \ mol 	imes 16 \ g/mol = 20.8 \ g$.

Calculate the mass of oxygen present in $0.1 \ mol$ of $Na_2CO_3 \cdot 10H_2O$. (in $g$)

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