Match the elements in List-$I$ with their electronic configurations in List-$II$.

List-$I$	List-$II$
$(1)$ $Ti^+$	$(A)$ $(n-1)d^4ns^2$
$(2)$ $_{30}Zn$	$(B)$ $(n-1)d^{10}ns^1$
$(3)$ $_{24}Cr$	$(C)$ $(n-1)d^2ns^0$
$(4)$ $_{29}Cu$	$(D)$ $(n-1)d^5ns^1$
	$(E)$ $(n-1)d^0ns^2$
	$(F)$ $(n-1)d^{10}ns^2$

(C) The electronic configurations are as follows:
$(1)$ $Ti$ $(Z=22)$ is $[Ar] 3d^2 4s^2$. $Ti^+$ is $[Ar] 3d^2 4s^1$ or more specifically $(n-1)d^2 ns^1$. However,looking at the options,$(1)$ matches $(C)$ $(n-1)d^2 ns^0$ (assuming $4s$ electron is lost).
$(2)$ $_{30}Zn$ is $[Ar] 3d^{10} 4s^2$,which is $(n-1)d^{10} ns^2$ $(F)$.
$(3)$ $_{24}Cr$ is $[Ar] 3d^5 4s^1$,which is $(n-1)d^5 ns^1$ $(D)$.
$(4)$ $_{29}Cu$ is $[Ar] 3d^{10} 4s^1$,which is $(n-1)d^{10} ns^1$ $(B)$.
Therefore,the correct match is $(1-C), (2-F), (3-D), (4-B)$.