$He_{2}$ molecule is not possible. Explain.
(N/A) $He$ $(Z=2)$,so the total number of electrons in $He_{2}$ is $4$.
The molecular orbital $(MO)$ electronic configuration of $He_{2}$ is: $(\sigma_{1s})^{2} (\sigma_{1s}^{*})^{2}$.
All electrons are paired in $He_{2}$,so it is diamagnetic.
Bond order $= \frac{1}{2} (N_{b} - N_{a}) = \frac{1}{2} (2 - 2) = 0$.
Since the bond order of $He_{2}$ is $0$,the molecule is unstable and does not exist.
The $MO$ energy diagram of $He_{2}$ is shown below.
The molecular orbital $(MO)$ electronic configuration of $He_{2}$ is: $(\sigma_{1s})^{2} (\sigma_{1s}^{*})^{2}$.
All electrons are paired in $He_{2}$,so it is diamagnetic.
Bond order $= \frac{1}{2} (N_{b} - N_{a}) = \frac{1}{2} (2 - 2) = 0$.
Since the bond order of $He_{2}$ is $0$,the molecule is unstable and does not exist.
The $MO$ energy diagram of $He_{2}$ is shown below.
Explore More
Similar Questions
For a stable molecule,the value of bond order must be
In the process,$O_2^+ \to O_2^{2+} + e^-$,the electron lost is from:
Easy
View SolutionThe sum of the bond orders of $O_2^{2+}, O_2^{2-}, O_2^{+}, O_2^{-}, O_2$ and the sum of the unpaired electrons present in them respectively are
What is meant by the term bond order? Calculate the bond order of: $N_{2}, O_{2}, O_{2}^{+}$ and $O_{2}^{-}$
Difficult
View SolutionExplain the linear combination of atomic orbitals $(LCAO)$ with a suitable example.
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo