To which type does ClF_3 belong among AB_4,AB | vedclass

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Question

(C) $1$. The central atom in $ClF_3$ is Chlorine $(Cl)$.$2$. The valence shell configuration of $Cl$ is $ns^2 np^5$,having $7$ valence electrons.$3$.

Vedclass · Accepted Answer

$AB_3E_2$

Vedclass · Answer

(C) $1$. The central atom in $ClF_3$ is Chlorine $(Cl)$.$2$. The valence shell configuration of $Cl$ is $ns^2 np^5$,having $7$ valence electrons.$3$. In $ClF_3$,$Cl$ forms $3$ single bonds with $3$ Fluorine $(F)$ atoms,utilizing $3$ valence electrons.$4$. The remaining $4$ electrons form $2$ lone pairs $(E_2)$.$5$. Thus,the molecule follows the $AB_3E_2$ type,where $A$ is the central atom,$B$ is the bonded atom,and $E$ represents the lone pair.$6$. The geometry is $T$-shaped due to the presence of $2$ lone pairs.

List-$I$	List-$II$
$(a)$ $PCl_{5}$	$(i)$ Square pyramidal
$(b)$ $SF_{6}$	$(ii)$ Trigonal planar
$(c)$ $BrF_{5}$	$(iii)$ Octahedral
$(d)$ $BF_{3}$	$(iv)$ Trigonal bipyramidal

To which type does $ClF_3$ belong among $AB_4$,$AB_4E$,and $AB_3E_2$? Explain.

Similar Questions

In which of the following is the angle between the two covalent bonds greatest?

Match List-$I$ with List-$II$.

List-$I$ List-$II$

$(a)$ $PCl_{5}$ $(i)$ Square pyramidal

$(b)$ $SF_{6}$ $(ii)$ Trigonal planar

$(c)$ $BrF_{5}$ $(iii)$ Octahedral

$(d)$ $BF_{3}$ $(iv)$ Trigonal bipyramidal

Choose the correct answer from the options given below.

The structure of $PF_5$ molecule is

The shape of the $BF_3$ molecule is:

What is the number of bond pair of electrons and lone pair of electrons present in the valence shell of chalcogens in their hydrides $(H_2X)$?

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