Match the type of hybridization given in List | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The hybridization of the given species is as follows: $(1)$ $[PtCl_4]^{2-}$ involves $dsp^2$ hybridization (square planar). $(2)$ $BrF_5$ involves

Vedclass · Accepted Answer

$1-C, 2-A, 3-D, 4-B$

Vedclass · Answer

(A) The hybridization of the given species is as follows: $(1)$ $[PtCl_4]^{2-}$ involves $dsp^2$ hybridization (square planar). $(2)$ $BrF_5$ involves $sp^3d^2$ hybridization (square pyramidal). $(3)$ $PCl_5$ involves $sp^3d$ hybridization (trigonal bipyramidal). $(4)$ $[Co(NH_3)_6]^{3+}$ involves $d^2sp^3$ hybridization (octahedral). Therefore,the correct matching is $1-C, 2-A, 3-D, 4-B$.

List-$I$	List-$II$
$(1)$ $dsp^2$	$(A)$ $BrF_5$
$(2)$ $sp^3d^2$	$(B)$ $[Co(NH_3)_6]^{3+}$
$(3)$ $sp^3d$	$(C)$ $[PtCl_4]^{2-}$
$(4)$ $d^2sp^3$	$(D)$ $PCl_5$

Match the type of hybridization given in List-$I$ with the molecules/ions given in List-$II$.

List-$I$ List-$II$

$(1)$ $dsp^2$ $(A)$ $BrF_5$

$(2)$ $sp^3d^2$ $(B)$ $[Co(NH_3)_6]^{3+}$

$(3)$ $sp^3d$ $(C)$ $[PtCl_4]^{2-}$

$(4)$ $d^2sp^3$ $(D)$ $PCl_5$

Similar Questions

The number of unpaired electrons in $Ni(CO)_4$ is

Which one of the following has a square planar geometry?

The shape of pentacarbonyl iron,$Fe(CO)_5$,is:

Which of the following has a square planar geometry?
(At. nos.: $Fe=26, Co=27, Ni=28, Pt=78$)

$[Cu(NH_3)_4]^{2+}$ shows the following hybridization:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Match the type of hybridization given in List-$I$ with the molecules/ions given in List-$II$. List-$I$ List-$II$ $(1)$ $dsp^2$ $(A)$ $BrF_5$ $(2)$ $sp^3d^2$ $(B)$ $[Co(NH_3)_6]^{3+}$ $(3)$ $sp^3d$ $(C)$ $[PtCl_4]^{2-}$ $(4)$ $d^2sp^3$ $(D)$ $PCl_5$