What is the type of hybridization of the cent | vedclass

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(A) $1$. For $BeCl_2$: The central atom $Be$ has $2$ valence electrons and forms $2$ bonds with $Cl$. Steric number = $2 + 0 = 2$,so hybridization is

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$sp, sp, sp^2, sp^2$

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(A) $1$. For $BeCl_2$: The central atom $Be$ has $2$ valence electrons and forms $2$ bonds with $Cl$. Steric number = $2 + 0 = 2$,so hybridization is $sp$.$2$. For $CO_2$: The central atom $C$ has $4$ valence electrons and forms $2$ double bonds with $O$. Steric number = $2 + 0 = 2$,so hybridization is $sp$.$3$. For $BH_3$: The central atom $B$ has $3$ valence electrons and forms $3$ bonds with $H$. Steric number = $3 + 0 = 3$,so hybridization is $sp^2$.$4$. For $BCl_3$: The central atom $B$ has $3$ valence electrons and forms $3$ bonds with $Cl$. Steric number = $3 + 0 = 3$,so hybridization is $sp^2$.Thus,the hybridization sequence is $sp, sp, sp^2, sp^2$.

What is the type of hybridization of the central atom in the following molecules: $BeCl_2, CO_2, BH_3, BCl_3$?

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