What is the dependence of interaction energy on the distance $(r)$ between molecules for the following forces?
$(i)$ London forces
$(ii)$ Dipole-dipole forces (stationary)
$(iii)$ Dipole-induced dipole forces

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The interaction energy $(V)$ between molecules depends on the distance $(r)$ as follows:
$(i)$ For London dispersion forces,$V \propto \frac{1}{r^{6}}$.
$(ii)$ For stationary dipole-dipole forces,$V \propto \frac{1}{r^{3}}$.
$(iii)$ For dipole-induced dipole forces,$V \propto \frac{1}{r^{6}}$.

Explore More

Similar Questions

Inert gases are mixed in iodine vapours. Then there are . . . . . . between them.

The formation of energy bonds in solids is in accordance with:

Arrange the following forces in the increasing order of their interaction energy:
London forces,Covalent bond,Hydrogen bond,Dipole-dipole forces

Which of the following exhibits the weakest intermolecular forces?

Metallic lustre is due to

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo