If the density ratio of a gas is 1:2 and the | vedclass

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(A) From the ideal gas equation,$PV = nRT$,we know $PV = (\frac{m}{M})RT$,which gives $P = (\frac{d}{M})RT$,where $d$ is the density.Therefore,$P = \f

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$1:1$

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(A) From the ideal gas equation,$PV = nRT$,we know $PV = (\frac{m}{M})RT$,which gives $P = (\frac{d}{M})RT$,where $d$ is the density.Therefore,$P = \frac{dRT}{M}$.Given $\frac{d_1}{d_2} = \frac{1}{2}$ and $\frac{T_1}{T_2} = \frac{2}{1}$.Taking the ratio of pressures: $\frac{P_1}{P_2} = (\frac{d_1}{d_2}) 	imes (\frac{T_1}{T_2}) = \frac{1}{2} 	imes \frac{2}{1} = \frac{1}{1}$.Thus,the ratio of their pressures is $1:1$.

If the density ratio of a gas is $1:2$ and the temperature ratio is $2:1$,what will be the ratio of their pressures?

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