The solubility product of $AgI$ at $25^{\circ} C$ is $1.0 \times 10^{-16} \ mol^2 \ L^{-2}$. What is the solubility of $AgI$ in $10^{-4} \ N \ KI$ at $25^{\circ} C$?
- A$1.0 \times 10^{-12} \ mol \ L^{-1}$
- B$1.0 \times 10^{-16} \ mol \ L^{-1}$
- C$1.0 \times 10^{-8} \ mol \ L^{-1}$
- D$2.0 \times 10^{-16} \ mol \ L^{-1}$
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Similar Questions
Match the following metal sulfides with their respective solubility product $(K_{sp})$ values:
Metal sulfide Solubility product $A$. $PbS$ $I$. $4.0 \times 10^{-53}$ $B$. $HgS$ $II$. $8.0 \times 10^{-28}$ $C$. $MnS$ $III$. $1.6 \times 10^{-24}$ $D$. $ZnS$ $IV$. $2.5 \times 10^{-13}$
| Metal sulfide | Solubility product |
|---|---|
| $A$. $PbS$ | $I$. $4.0 \times 10^{-53}$ |
| $B$. $HgS$ | $II$. $8.0 \times 10^{-28}$ |
| $C$. $MnS$ | $III$. $1.6 \times 10^{-24}$ |
| $D$. $ZnS$ | $IV$. $2.5 \times 10^{-13}$ |
Two insoluble salts $MY$ and $NY_{3}$ have the same $K_{SP} = 6.2 \times 10^{-13}$ at room temperature. Which of the following statements is true regarding $MY$ and $NY_{3}$?
Medium
View SolutionFor a sparingly soluble salt $AB_2$,the equilibrium concentrations of $A^{2+}$ ions and $B^{-}$ ions are $1.2 \times 10^{-4} \ M$ and $0.24 \times 10^{-3} \ M$,respectively. The solubility product of $AB_2$ is :
The solubility product $({K_{sp}})$ of $BaCO_3$ is $1.5 \times 10^{-9}$. At what concentration of $Ba^{2+}$ ions will precipitation begin when solid $Ba(NO_3)_2$ is added to a $10^{-4} \ M$ solution of $Na_2CO_3$?
Difficult
View SolutionWhich one of the following arrangements represents the correct order of solubilities of sparingly soluble salts $Hg_2Cl_2$,$Cr_2(SO_4)_3$,$BaSO_4$ and $CrCl_3$ respectively?
DifficultJEE MAIN 2013
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