For the exothermic reaction $Cl_{2(g)} + 3F_{2(g)} \rightleftharpoons 2ClF_{3(g)}$,$\Delta_r H = -329 \ kJ$,which of the following will increase the quantity of $ClF_3$ in the equilibrium mixture?

For the reaction $aA + bB \rightleftharpoons cC + dD$,if the equilibrium shifts in the backward direction at low pressure and high temperature,which of the following is correct?

Consider the following equation:
$2 SO_{2(g)} + O_{2(g)} \rightleftharpoons 2 SO_{3(g)}, \Delta H = -190 \ kJ$
The number of factors which will increase the yield of $SO_3$ at equilibrium from the following is $.............$.
$A.$ Increasing temperature
$B.$ Increasing pressure
$C.$ Adding more $SO_2$
$D.$ Adding more $O_2$
$E.$ Addition of catalyst

Does the number of moles of reaction products increase,decrease,or remain the same when each of the following equilibria is subjected to a decrease in pressure by increasing the volume?
$(a) \quad PCl_{5(g)} \longleftrightarrow PCl_{3(g)} + Cl_{2(g)}$
$(b) \quad CaO_{(s)} + CO_{2(g)} \longleftrightarrow CaCO_{3(s)}$
$(c) \quad 3Fe_{(s)} + 4H_2O_{(g)} \longleftrightarrow Fe_3O_{4(s)} + 4H_{2(g)}$

Which of the following conditions is favorable for the forward reaction in the equilibrium: $H_2 \rightleftharpoons H + H$ $(\Delta H = +ve)$?

For the reaction $2SO_2(g) + O_2(g) \rightleftharpoons 2SO_3(g)$,$\Delta H^o = -198 \, kJ$. According to Le Chatelier's principle,the favorable conditions for the forward reaction are: