$0.08 \ g$ of $CaF_2$ is dissolved in $2.90 \ L$ of water to form a saturated solution at $298 \ K$. Calculate the solubility product constant $(K_{sp})$ of $CaF_2$. (Molar mass of $CaF_2 = 78.08 \ g/mol$)

  • A
    $1.767 \times 10^{-10}$
  • B
    $3.534 \times 10^{-10}$
  • C
    $8.835 \times 10^{-11}$
  • D
    $4.417 \times 10^{-11}$

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