Match the reactants in Column-$(I)$ with the products formed in Column-$(II)$.

Column-$(I)$ (Reactants)	Column-$(II)$ (Major Products)
$(A)$ $C_6H_5CH_3 + X_2 \xrightarrow{Fe, \text{dark}}$	$(i)$ $C_6H_5CH(Br)CH_3$
$(B)$ $C_6H_5NH_2 \xrightarrow{NaNO_2, HX, 273-278 \ K}$	$(ii)$ $C_6H_5N_2^+X^-$
$(C)$ $C_6H_5N_2^+X^- \xrightarrow{Cu_2X_2}$	$(iii)$ $p-X-C_6H_4CH_3 + o-X-C_6H_4CH_3$
$(D)$ $C_6H_5CH_2CH_3 \xrightarrow{Br_2, \Delta \text{ or } UV \text{ light}}$	$(iv)$ $C_6H_5X$

(A-III, B-II, C-IV, D-I) $(A \rightarrow iii)$: Electrophilic aromatic substitution of toluene with $X_2$ in the presence of $Fe$ (dark) gives ortho and para halo-substituted toluene.
$(B \rightarrow ii)$: Aniline reacts with $NaNO_2$ and $HX$ at $273-278 \ K$ to form benzene diazonium salt.
$(C \rightarrow iv)$: Sandmeyer reaction of benzene diazonium salt with $Cu_2X_2$ yields aryl halide $(C_6H_5X)$.
$(D \rightarrow i)$: Free radical bromination of ethylbenzene with $Br_2$ under light/heat occurs at the benzylic position to form $1$-bromo-$1$-phenylethane.