0.1914 g of an organic acid is dissolved in | vedclass

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Question

(C) At the equivalence point,the number of equivalents of acid equals the number of equivalents of base.$Equivalents 	ext{ of acid} = 	ext{Equivalen

Vedclass · Accepted Answer

$63.8$

Vedclass · Answer

(C) At the equivalence point,the number of equivalents of acid equals the number of equivalents of base.$Equivalents 	ext{ of acid} = 	ext{Equivalents of } NaOH$$\frac{	ext{Mass of acid}}{	ext{Equivalent weight}} = 	ext{Normality} 	imes 	ext{Volume (in L)}$$\frac{0.1914}{E} = 0.12 	imes \frac{25}{1000}$$E = \frac{0.1914 	imes 1000}{0.12 	imes 25}$$E = \frac{191.4}{3} = 63.8$Therefore,the equivalent weight of the acid is $63.8$.

Isotope	$\%$ Natural abundance	Molar mass
$^1H$	$99.985$	$1$
$^2H$	$0.015$	$2$

$0.1914 \ g$ of an organic acid is dissolved in approx. $20 \ mL$ of water. $25 \ mL$ of $0.12 \ N$ $NaOH$ is required for the complete neutralization of the acid solution. The equivalent weight of the acid is

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