Match the reactants in Column-$I$ with the major products in Column-$II$.

Column-$I$ (Reactants)	Column-$II$ (Products)
$(A)$ $HCHO + \text{Cyclohexyl-MgBr} \rightarrow X \xrightarrow{H_2O} Y$	$(i)$ $\text{Benzenesulfonic acid}$
$(B)$ $\text{2-oxocyclohexylacetate} \xrightarrow{NaBH_4}$	$(ii)$ $\text{Cyclohexylmethanol}$
$(C)$ $HCHO + CH_3-CH_2-CH(CH_3)-CH_2-MgBr \rightarrow X \xrightarrow{H_2O} Y$	$(iii)$ $\text{2-(2-hydroxycyclohexyl)acetate}$
$(D)$ $\text{Benzene} + \text{Oleum}$	$(iv)$ $Y = \text{3-methylpentan-1-ol}$

(A-II, B-III, C-IV, D-I) $HCHO$ reacts with $\text{Cyclohexyl-MgBr}$ to form a primary alcohol, $\text{Cyclohexylmethanol}$ $(ii)$.
$(B)$ $NaBH_4$ selectively reduces the ketone group to an alcohol, yielding $\text{2-(2-hydroxycyclohexyl)acetate}$ $(iii)$.
$(C)$ $HCHO$ reacts with $CH_3-CH_2-CH(CH_3)-CH_2-MgBr$ to form a primary alcohol, $\text{3-methylpentan-1-ol}$ $(iv)$.
$(D)$ $\text{Benzene}$ reacts with $\text{Oleum}$ $(H_2SO_4 + SO_3)$ to undergo sulfonation, forming $\text{Benzenesulfonic acid}$ $(i)$.
Thus, the correct matching is: $(A-ii, B-iii, C-iv, D-i)$.