Match the reactions given in Column-$I$ with the conditions given in Column-$II$.

Column-$I$ (Reaction)	Column-$II$ (Condition)
$(A)$ $CH_3-CH(OH)-CH_3 \rightarrow CH_3-CH=CH_2$	$(i)$ $20\% \ H_3PO_4, 358 \ K$
$(B)$ $CH_3-C(CH_3)_2-OH \rightarrow CH_3-C(CH_3)=CH_2$	(ii) $Cu, 573 \ K$
$(C)$ $CH_3CH_2OH \rightarrow CH_2=CH_2 + H_2O$	(iii) $85\% \ H_3PO_4, 440 \ K$
$(D)$ $R-CH(OH)-R' \rightarrow R-CO-R'$	(iv) $H_2SO_4, 443 \ K$

(A) $CH_3-CH(OH)-CH_3$ is a secondary alcohol. Dehydration of secondary alcohol requires $85\% \ H_3PO_4$ at $440 \ K$ $(A \rightarrow iii)$.
$(B)$ $CH_3-C(CH_3)_2-OH$ is a tertiary alcohol. Dehydration of tertiary alcohol occurs easily with $20\% \ H_3PO_4$ at $358 \ K$ $(B \rightarrow i)$.
$(C)$ $CH_3CH_2OH$ is a primary alcohol. Dehydration of primary alcohol requires concentrated $H_2SO_4$ at $443 \ K$ $(C \rightarrow iv)$.
$(D)$ Oxidation of secondary alcohol $(R-CH(OH)-R')$ with $Cu$ at $573 \ K$ gives a ketone $(R-CO-R')$ $(D \rightarrow ii)$.
Therefore,the correct match is: $(A$ $\rightarrow iii), (B$ $\rightarrow i), (C$ $\rightarrow iv), (D$ $\rightarrow ii)$.