[P] on treatment with Br_{2}/FeBr_{3} in CCl_ | vedclass

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Question

(D) $1$. Heating $[P]$ with sodalime $(NaOH + CaO)$ causes decarboxylation,yielding toluene $(C_6H_5CH_3)$. This implies $[P]$ is a toluic acid isomer

Vedclass · Accepted Answer

$p$-Toluic acid

Vedclass · Answer

(D) $1$. Heating $[P]$ with sodalime $(NaOH + CaO)$ causes decarboxylation,yielding toluene $(C_6H_5CH_3)$. This implies $[P]$ is a toluic acid isomer $(CH_3C_6H_4COOH)$.$2$. Bromination of $[P]$ with $Br_2/FeBr_3$ is an electrophilic aromatic substitution reaction. The $-CH_3$ group is ortho/para-directing,and the $-COOH$ group is meta-directing.$3$. In $p$-toluic acid,both groups direct the incoming bromine to the same position (ortho to $-CH_3$ and meta to $-COOH$),resulting in a single isomer: $3$-bromo-$4$-methylbenzoic acid.$4$. Therefore,$[P]$ is $p$-toluic acid.

$[P]$ on treatment with $Br_{2}/FeBr_{3}$ in $CCl_{4}$ produced a single isomer $C_{8}H_{7}O_{2}Br$ while heating $[P]$ with sodalime gave toluene. The compound $[P]$ is:

Similar Questions

Rank the following compounds in order of decreasing rate of reaction with alkoxide ion $(CH_3CH_2O^{-})$ in a nucleophilic aromatic substitution reaction:
$1$. $1$-bromo-$2$-nitrobenzene
$2$. $1$-bromo-$3$-nitrobenzene
$3$. $1$-bromo-$2,4$-dinitrobenzene
$4$. $1$-bromo-$3,4$-dinitrobenzene

The reaction of toluene with chlorine in the presence of ferric chloride $(FeCl_3)$ gives predominantly:

The reaction of an aryl halide with an alkyl halide and sodium metal in dry ether to form substituted aromatic compounds is known as:

Which reaction shows the correct major product?

Assertion : Cyanide $(CN^{-})$ is a strong nucleophile.
Reason : Benzonitrile is prepared by the reaction of chlorobenzene with potassium cyanide.

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