The IUPAC name of the compound CH_3-CH_2-CH_2 | vedclass

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(C) $1$. Identify the longest carbon chain. The longest chain contains $10$ carbon atoms,which is a decane chain.$2$. Number the chain from the end th

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$4,5$-dimethyl-$4$-ethyldecane

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(C) $1$. Identify the longest carbon chain. The longest chain contains $10$ carbon atoms,which is a decane chain.$2$. Number the chain from the end that gives the substituents the lowest possible locants. Numbering from the right gives the substituents at positions $4$ and $5$.$3$. At position $4$,there is an ethyl group $(-CH_2-CH_3)$ and a methyl group $(-CH_3)$. At position $5$,there is another methyl group $(-CH_3)$.$4$. Combining these,the name is $4$-ethyl-$4,5$-dimethyldecane,which is alphabetically ordered as $4,5$-dimethyl-$4$-ethyldecane.

The $IUPAC$ name of the compound $CH_3-CH_2-CH_2-CH_2-CH_2-CH(CH_3)-C(CH_3)(CH_2-CH_2-CH_3)-CH_2-CH_3$ is:

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