In an examination,37 frac{1}{2} % of the cand | vedclass

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(D) Let the total number of candidates be $x$.Percentage of girls $= 37 \frac{1}{2} \% = \frac{75}{2} \% = \frac{3}{8}$.Percentage of boys $= 100 \% -

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$380$

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(D) Let the total number of candidates be $x$.Percentage of girls $= 37 \frac{1}{2} \% = \frac{75}{2} \% = \frac{3}{8}$.Percentage of boys $= 100 \% - 37 \frac{1}{2} \% = 62 \frac{1}{2} \% = \frac{125}{2} \% = \frac{5}{8}$.Number of girls $= \frac{3}{8}x$ and number of boys $= \frac{5}{8}x$.Girls who failed $= (100 - 62 \frac{1}{2}) \% = 37 \frac{1}{2} \% = \frac{3}{8}$ of the girls.Given,$\frac{3}{8} 	imes (\frac{3}{8}x) = 342$.$\frac{9}{64}x = 342 \implies x = \frac{342 	imes 64}{9} = 38 	imes 64 = 2432$.Boys who failed $= (100 - 75) \% = 25 \% = \frac{1}{4}$ of the boys.Number of boys who failed $= \frac{1}{4} 	imes (\frac{5}{8}x) = \frac{5}{32}x$.Substituting $x = 2432$,we get $\frac{5}{32} 	imes 2432 = 5 	imes 76 = 380$.

In an examination,$37 \frac{1}{2} \%$ of the candidates were girls. If $75 \%$ of the boys and $62 \frac{1}{2} \%$ of the girls passed,and $342$ girls failed,find the number of boys who failed.

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