If the distance between two consecutive base | vedclass

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Question

(C) The length of $DNA$ is calculated by multiplying the total number of base pairs by the distance between two consecutive base pairs.Given:Total num

Vedclass · Accepted Answer

$2.2$

Vedclass · Answer

(C) The length of $DNA$ is calculated by multiplying the total number of base pairs by the distance between two consecutive base pairs.Given:Total number of base pairs = $6.6 	imes 10^9 \ bp$Distance between two base pairs = $0.34 \ nm = 0.34 	imes 10^{-9} \ m$Length of $DNA$ = $(	ext{Total number of base pairs}) 	imes (	ext{Distance between two base pairs})$Length of $DNA$ = $(6.6 	imes 10^9) 	imes (0.34 	imes 10^{-9} \ m)$Length of $DNA$ = $6.6 	imes 0.34 \ m$Length of $DNA$ = $2.244 \ m \approx 2.2 \ m$.Therefore,the correct option is $C$.

Column $I$	Column $II$
$(A) 5386$ nucleotides	$(p) E. coli$
$(B) 48502$ bp	$(q) \text{Man}$
$(C) 4.6 \times 10^6$ bp	$(r) \text{Drosophila}$
$(D) 3.3 \times 10^9$ bp	$(s) \phi \times 174 \text{ bacteriophage}$
	$(t) \text{Bacteriophage lambda}$

If the distance between two consecutive base pairs in a $DNA$ molecule is $0.34 \ nm$ and the total number of base pairs in a typical mammalian cell is $6.6 \times 10^9 \ bp$,what is the approximate length of the $DNA$ (in $m$)?

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