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(C) In alloy $A$,the ratio of gold to copper is $7:2$. The total parts are $7+2=9$.In alloy $B$,the ratio of gold to copper is $7:11$. The total parts

Vedclass · Accepted Answer

$7:5$

Vedclass · Answer

(C) In alloy $A$,the ratio of gold to copper is $7:2$. The total parts are $7+2=9$.In alloy $B$,the ratio of gold to copper is $7:11$. The total parts are $7+11=18$.Since equal quantities of alloys $A$ and $B$ are mixed,we must make the total parts equal in both alloys.To make the total parts equal to $18$,multiply the ratio of alloy $A$ by $2$:Alloy $A = (7 	imes 2) : (2 	imes 2) = 14:4$.Now,alloy $A$ has $14$ parts gold and $4$ parts copper (total $18$ parts).Alloy $B$ has $7$ parts gold and $11$ parts copper (total $18$ parts).When mixed to form alloy $C$,the total gold is $14+7=21$ and the total copper is $4+11=15$.The ratio of gold to copper in alloy $C$ is $21:15$.Simplifying the ratio by dividing by $3$,we get $7:5$.

$A$ and $B$ are two alloys of gold and copper prepared by mixing metals in the ratio $7:2$ and $7:11$ respectively. If equal quantities of the alloys are melted to form a third alloy $C$,the ratio of gold and copper in $C$ will be

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