A, B and C can complete a work in 2 , h. If A | vedclass

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(B) The work done by $A, B$ and $C$ together in $1 \, h$ is $\frac{1}{2}$ of the total work.The work done by $A$ alone in $1 \, h$ is $\frac{1}{6}$ of

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$7 \frac{1}{2}$

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(B) The work done by $A, B$ and $C$ together in $1 \, h$ is $\frac{1}{2}$ of the total work.The work done by $A$ alone in $1 \, h$ is $\frac{1}{6}$ of the total work.The work done by $B$ alone in $1 \, h$ is $\frac{1}{5}$ of the total work.Let the work done by $C$ alone in $1 \, h$ be $x$.Therefore,$\frac{1}{6} + \frac{1}{5} + x = \frac{1}{2}$.$x = \frac{1}{2} - (\frac{1}{6} + \frac{1}{5}) = \frac{1}{2} - \frac{5+6}{30} = \frac{1}{2} - \frac{11}{30}$.$x = \frac{15-11}{30} = \frac{4}{30} = \frac{2}{15}$.So,$C$ finishes $\frac{2}{15}$ of the work in $1 \, h$. The time taken by $C$ to finish the whole work is $\frac{15}{2} = 7.5 \, h$ or $7 \frac{1}{2} \, h$.

$A, B$ and $C$ can complete a work in $2 \, h$. If $A$ does the job alone in $6 \, h$ and $B$ in $5 \, h$,how long will it take for $C$ to finish the job alone? (in $h$)

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