(C) The work done by $A$ in $1 \text{ day} = \frac{1}{10}$.The work done by $B$ in $1 \text{ day} = \frac{1}{15}$.Since they work on alternate days st

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(C) The work done by $A$ in $1 \text{ day} = \frac{1}{10}$.The work done by $B$ in $1 \text{ day} = \frac{1}{15}$.Since they work on alternate days starting with $A$,the work done in a cycle of $2 \text{ days}$ is: $\frac{1}{10} + \frac{1}{15} = \frac{3+2}{30} = \frac{5}{30} = \frac{1}{6}$.This means in $2 \text{ days}$,$\frac{1}{6}$ of the work is completed.To complete the whole work ($1$ unit),we need $6$ such cycles.Total days $= 6 \times 2 = 12 \text{ days}$.

Competitive Quantitative Aptitude Time and Work and Wages Time and Work

Easy

$A$ and $B$ working separately can do a piece of work in $10 \text{ days}$ and $15 \text{ days}$ respectively. If they work on alternate days beginning with $A$,in how many days will the work be completed?

A
$18$
B
$13$
C
$12$
D
$6$

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Time and Work and Wages

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Time and Work

Some carpenters promised to do a job in $9$ days,but $5$ of them were absent and the remaining men did the job in $12$ days. The original number of carpenters was:

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$A$ is $30\%$ more efficient than $B.$ How much time will they,working together,take to complete a job which $A$ alone could have done in $23$ days? (in days)

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Bindal can finish a work in $10$ days. Jindal is twice as efficient as Bindal. If they work together,in how many days will the work be completed?

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If $A$ and $B$ together can complete a work in $18$ days,$A$ and $C$ together in $12$ days,and $B$ and $C$ together in $9$ days,then $B$ alone can do the work in (in days)

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$A$ and $B$ can do a work in $12$ days,$B$ and $C$ in $15$ days,and $C$ and $A$ in $20$ days. If $A, B,$ and $C$ work together,they will complete the work in (in days):

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$A$ and $B$ working separately can do a piece of work in $10 \text{ days}$ and $15 \text{ days}$ respectively. If they work on alternate days beginning with $A$,in how many days will the work be completed?

Similar Questions

Some carpenters promised to do a job in $9$ days,but $5$ of them were absent and the remaining men did the job in $12$ days. The original number of carpenters was:

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