A works thrice as good as B and is,therefore, | vedclass

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(B) Let $B$ take $x$ days to do the work.Then,$A$ takes $(x - 60)$ days to complete the work.Since the ratio of efficiency (work done per day) of $A$

Vedclass · Accepted Answer

$22 \frac{1}{2}$

Vedclass · Answer

(B) Let $B$ take $x$ days to do the work.Then,$A$ takes $(x - 60)$ days to complete the work.Since the ratio of efficiency (work done per day) of $A$ and $B$ is $3:1$,the ratio of time taken by $A$ and $B$ is $1:3$.We have,$\frac{x - 60}{x} = \frac{1}{3}$.$\Rightarrow 3(x - 60) = x \Rightarrow 3x - 180 = x \Rightarrow 2x = 180 \Rightarrow x = 90$.Therefore,time taken by $B = 90 	ext{ days}$ and time taken by $A = 90 - 60 = 30 	ext{ days}$.Working together,they will complete the work in $\frac{A 	imes B}{A + B} = \frac{30 	imes 90}{30 + 90} = \frac{2700}{120} = \frac{270}{12} = 22.5 	ext{ days}$.Thus,the time taken is $22 \frac{1}{2} 	ext{ days}$.

$A$ works thrice as good as $B$ and is,therefore,able to finish a piece of work in $60 \text{ days}$ less than $B$. Find the time in which they can complete it,working together (in $\text{days}$).

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