4 men and 6 women complete a work in 8 days,2 | vedclass

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(D) Let $M$ be the work done by a man in one day and $W$ be the work done by a woman in one day.According to the problem:$(4M + 6W) 	imes 8 = (2M + 9

Vedclass · Accepted Answer

$5 \frac{1}{3}$

Vedclass · Answer

(D) Let $M$ be the work done by a man in one day and $W$ be the work done by a woman in one day.According to the problem:$(4M + 6W) 	imes 8 = (2M + 9W) 	imes 8$Dividing both sides by $8$,we get:$4M + 6W = 2M + 9W$$2M = 3W$This means $2$ men are equivalent to $3$ women.Now,substitute $2M = 3W$ into the first case:$4M + 6W = 2(2M) + 6W = 2(3W) + 6W = 6W + 6W = 12W$.So,$12$ women can complete the work in $8$ days.To find the time taken by $18$ women,we use the formula $W_1 	imes D_1 = W_2 	imes D_2$:$12 	imes 8 = 18 	imes D_2$$D_2 = \frac{12 	imes 8}{18} = \frac{96}{18} = \frac{16}{3} = 5 \frac{1}{3}$ days.

$4$ men and $6$ women complete a work in $8$ days,$2$ men and $9$ women also complete the same work in $8$ days. In how many days will $18$ women complete the work?

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