ABCD is a parallelogram as shown in the figur | vedclass

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Question

(A) The area of a parallelogram is given by the formula: $	ext{Area} = 	ext{base} 	imes 	ext{height}$.In the given figure,the base $CD$ is $3 	ex

Vedclass · Accepted Answer

$12$

Vedclass · Answer

(A) The area of a parallelogram is given by the formula: $	ext{Area} = 	ext{base} 	imes 	ext{height}$.In the given figure,the base $CD$ is $3 	ext{ cm}$ and the corresponding height $BD$ is $4 	ext{ cm}$.Therefore,$	ext{Area} = 3 	ext{ cm} 	imes 4 	ext{ cm} = 12 	ext{ cm}^2$.Alternatively,the parallelogram is composed of two congruent triangles,$\Delta ABD$ and $\Delta BDC$.$	ext{Area of } \Delta BDC = \frac{1}{2} 	imes 	ext{base} 	imes 	ext{height} = \frac{1}{2} 	imes 3 	imes 4 = 6 	ext{ cm}^2$.$	ext{Total Area} = 2 	imes 6 	ext{ cm}^2 = 12 	ext{ cm}^2$.

$ABCD$ is a parallelogram as shown in the figure. Find its area in $cm^2$.

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