2 poles of heights 15, m and 30, m stand upri | vedclass

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(B) Let $AL$ and $BM$ be the two poles with heights $15\, m$ and $30\, m$ respectively,standing on the ground $AB = 36\, m$.Draw a line $LN$ parallel

Vedclass · Accepted Answer

$39$

Vedclass · Answer

(B) Let $AL$ and $BM$ be the two poles with heights $15\, m$ and $30\, m$ respectively,standing on the ground $AB = 36\, m$.Draw a line $LN$ parallel to $AB$ such that $LN = AB = 36\, m$ and $N$ lies on $BM$.Then,$BN = AL = 15\, m$.Therefore,$MN = BM - BN = 30\, m - 15\, m = 15\, m$.In the right-angled triangle $	riangle LNM$,by the Pythagorean theorem:$LM^2 = LN^2 + MN^2$$LM^2 = 36^2 + 15^2$$LM^2 = 1296 + 225 = 1521$$LM = \sqrt{1521} = 39\, m$.Thus,the distance between their tops is $39\, m$.

$2$ poles of heights $15\, m$ and $30\, m$ stand upright on a playground. If their feet are $36\, m$ apart,find the distance between their tops in meters.

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