(D) To find the value,we perform the calculation as follows:$? = \frac{1}{8} \times \frac{6}{7} \times 11200$First,divide $11200$ by $7$:$11200 \div 7

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(D) To find the value,we perform the calculation as follows:$? = \frac{1}{8} \times \frac{6}{7} \times 11200$First,divide $11200$ by $7$:$11200 \div 7 = 1600$Now,the expression becomes:$? = \frac{1}{8} \times 6 \times 1600$Next,divide $1600$ by $8$:$1600 \div 8 = 200$Finally,multiply by $6$:$? = 6 \times 200 = 1200$

Competitive Quantitative Aptitude Number system Numbers

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$\frac{1}{8}$ th of $\frac{6}{7}$ th of $11200 = ?$

A
$1100$
B
$1220$
C
$1430$
D
$1200$

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If a six-digit number $53a29b$ is divisible by $88$,then find the value of $a$ and $b$.

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What is the smallest $6$-digit number that is completely divisible by $108$?

Medium

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Which number should replace both the $$s in $\left(\frac{}{21}\right) \times \left(\frac{*}{189}\right) = 1$?

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The number of times $79$ must be subtracted from $50000$ so that the remainder is $43759$ is:

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The reciprocal of the sum of the reciprocals of $\frac{6}{5}$ and $\frac{3}{7}$ is:

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$\frac{1}{8}$ th of $\frac{6}{7}$ th of $11200 = ?$

Similar Questions

If a six-digit number $53a29b$ is divisible by $88$,then find the value of $a$ and $b$.

What is the smallest $6$-digit number that is completely divisible by $108$?

Which number should replace both the $*$s in $\left(\frac{*}{21}\right) \times \left(\frac{*}{189}\right) = 1$?

The number of times $79$ must be subtracted from $50000$ so that the remainder is $43759$ is:

The reciprocal of the sum of the reciprocals of $\frac{6}{5}$ and $\frac{3}{7}$ is:

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Which number should replace both the $$s in $\left(\frac{}{21}\right) \times \left(\frac{*}{189}\right) = 1$?