$90 \times \frac{6}{18} + 73 = ?$

The product of three consecutive even numbers is $4032$. The product of the first and the third number is $252$. What is five times the second number?

$(6990 \div 15) \times (468 \div 18) = ?$

For what value of $K$,the number $7236K2$ is divisible by $8$?

$\frac{601}{49} \times \frac{399}{81} \div \frac{29}{201} = ?$

For any integral value of $n$,$3^{2n} + 9n + 5$ when divided by $3$ leaves the remainder: