$9067 + 2065 - 8400 + 3045 - 1520 = ?$

On dividing a number by $38$, we get $90$ as quotient and $19$ as remainder. What is the number?

$4767$ exactly divides $xxx\,341$. The missing digits are:

$A$ boy added all natural numbers from $1$ to $12,$ however he added one number twice due to which the sum became $80.$ What is the number which he added twice?

The unit digit in the product $(2467)^{153} \times (341)^{72}$ is

$\sqrt{2601} - \sqrt{1156} + \sqrt{484} = ?$