1 frac{1}{4} + 1 frac{5}{9} times 1 frac{5}{8 | vedclass

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(A) To solve the expression $1 \frac{1}{4} + 1 \frac{5}{9} 	imes 1 \frac{5}{8} \div 6 \frac{1}{2}$,we follow the $BODMAS$ rule.First,convert the mixe

Vedclass · Accepted Answer

$1 \frac{23}{36}$

Vedclass · Answer

(A) To solve the expression $1 \frac{1}{4} + 1 \frac{5}{9} 	imes 1 \frac{5}{8} \div 6 \frac{1}{2}$,we follow the $BODMAS$ rule.First,convert the mixed fractions into improper fractions:$1 \frac{1}{4} = \frac{5}{4}$,$1 \frac{5}{9} = \frac{14}{9}$,$1 \frac{5}{8} = \frac{13}{8}$,and $6 \frac{1}{2} = \frac{13}{2}$.The expression becomes: $\frac{5}{4} + \frac{14}{9} 	imes \frac{13}{8} \div \frac{13}{2}$.Perform the division first: $\frac{13}{8} \div \frac{13}{2} = \frac{13}{8} 	imes \frac{2}{13} = \frac{2}{8} = \frac{1}{4}$.Now,the expression is: $\frac{5}{4} + \frac{14}{9} 	imes \frac{1}{4}$.Perform the multiplication: $\frac{14}{9} 	imes \frac{1}{4} = \frac{14}{36} = \frac{7}{18}$.Finally,add the terms: $\frac{5}{4} + \frac{7}{18}$.The least common multiple of $4$ and $18$ is $36$.$\frac{5 	imes 9}{36} + \frac{7 	imes 2}{36} = \frac{45}{36} + \frac{14}{36} = \frac{59}{36}$.Converting back to a mixed fraction: $\frac{59}{36} = 1 \frac{23}{36}$.

$1 \frac{1}{4} + 1 \frac{5}{9} \times 1 \frac{5}{8} \div 6 \frac{1}{2} = ?$

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