(C) First,convert the mixed fraction into an improper fraction: $6 \frac{35}{216} = \frac{6 \times 216 + 35}{216} = \frac{1296 + 35}{216} = \frac{1331

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(C) First,convert the mixed fraction into an improper fraction: $6 \frac{35}{216} = \frac{6 \times 216 + 35}{216} = \frac{1296 + 35}{216} = \frac{1331}{216}$. Now,find the cube root of the resulting fraction: $\sqrt[3]{\frac{1331}{216}} = \frac{\sqrt[3]{1331}}{\sqrt[3]{216}}$. Since $11^3 = 1331$ and $6^3 = 216$,we get: $\frac{11}{6}$.

Competitive Quantitative Aptitude Number system Numbers

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$\sqrt[3]{6 \frac{35}{216}}$ is equal to........

A
$\frac{13}{6}$
B
$\frac{7}{3}$
C
$\frac{11}{6}$
D
$\frac{11}{3}$

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$\sqrt[3]{6 \frac{35}{216}}$ is equal to........

Similar Questions

What is the remainder when $2468$ is divided by $37$?

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