15 frac{2}{3} times 3 frac{1}{6} + 6 frac{1}{ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Convert the mixed fractions into improper fractions:$15 \frac{2}{3} = \frac{47}{3}$,$3 \frac{1}{6} = \frac{19}{6}$,$6 \frac{1}{3} = \frac{19}{3}$,

Vedclass · Accepted Answer

$44 \frac{5}{9}$

Vedclass · Answer

(D) Convert the mixed fractions into improper fractions:$15 \frac{2}{3} = \frac{47}{3}$,$3 \frac{1}{6} = \frac{19}{6}$,$6 \frac{1}{3} = \frac{19}{3}$,$11 \frac{7}{18} = \frac{205}{18}$.Let the missing value be $x$.The equation becomes: $\frac{47}{3} 	imes \frac{19}{6} + \frac{19}{3} = \frac{205}{18} + x$.Calculate the product: $\frac{47 	imes 19}{3 	imes 6} = \frac{893}{18}$.Now,$\frac{893}{18} + \frac{19}{3} = \frac{205}{18} + x$.Convert $\frac{19}{3}$ to a fraction with denominator $18$: $\frac{19 	imes 6}{3 	imes 6} = \frac{114}{18}$.So,$\frac{893}{18} + \frac{114}{18} = \frac{205}{18} + x$.$\frac{1007}{18} = \frac{205}{18} + x$.$x = \frac{1007}{18} - \frac{205}{18} = \frac{802}{18}$.Simplifying $\frac{802}{18}$ by dividing by $2$: $\frac{401}{9}$.Converting $\frac{401}{9}$ to a mixed fraction: $44 \frac{5}{9}$.

$15 \frac{2}{3} \times 3 \frac{1}{6} + 6 \frac{1}{3} = 11 \frac{7}{18} + ?$

Similar Questions

The value of $(3+2 \sqrt{2})^{-3}+(3-2 \sqrt{2})^{-3}$ is

$\frac{5}{6} \div \frac{6}{7} \times ? - \frac{8}{9} \div 1 \frac{3}{5} + \frac{3}{4} \times 3 \frac{1}{3} = 2 \frac{7}{9}$

The least number to be subtracted from $16800$ to make it a perfect square is

What value will come in place of the question mark (?) in the following question? (You are not expected to calculate the exact value)
$10^{3} \times 100^{3} + 999999999 = 10^{?} + 10^{?}$

If $(x + \frac{1}{x})^2 = 3$,then $(x^3 + \frac{1}{x^3})$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module