frac{frac{64}{121}-frac{9}{64}}{frac{8}{11}+f | vedclass

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Question

(B) Given expression: $\frac{\frac{64}{121} - \frac{9}{64}}{\frac{8}{11} + \frac{3}{8}}$Numerator: $\frac{64}{121} - \frac{9}{64} = \frac{64^2 - 9 	i

Vedclass · Accepted Answer

$\frac{31}{88}$

Vedclass · Answer

(B) Given expression: $\frac{\frac{64}{121} - \frac{9}{64}}{\frac{8}{11} + \frac{3}{8}}$Numerator: $\frac{64}{121} - \frac{9}{64} = \frac{64^2 - 9 	imes 121}{121 	imes 64} = \frac{4096 - 1089}{7744} = \frac{3007}{7744}$Denominator: $\frac{8}{11} + \frac{3}{8} = \frac{8 	imes 8 + 3 	imes 11}{11 	imes 8} = \frac{64 + 33}{88} = \frac{97}{88}$Now,divide the numerator by the denominator:$\frac{3007}{7744} \div \frac{97}{88} = \frac{3007}{7744} 	imes \frac{88}{97}$Since $3007 = 31 	imes 97$ and $7744 = 88 	imes 88$:$= \frac{31 	imes 97}{88 	imes 88} 	imes \frac{88}{97} = \frac{31}{88}$

$\frac{\frac{64}{121}-\frac{9}{64}}{\frac{8}{11}+\frac{3}{8}} = ?$

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