frac{1}{6} of (92 %) of 1 frac{1}{23} of (650 | vedclass

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Question

(C) Let the missing value be $x$.The given equation is: $85 + x = \frac{1}{6} 	imes \frac{92}{100} 	imes \frac{24}{23} 	imes 650$Step $1$: Simplify

Vedclass · Accepted Answer

$19$

Vedclass · Answer

(C) Let the missing value be $x$.The given equation is: $85 + x = \frac{1}{6} 	imes \frac{92}{100} 	imes \frac{24}{23} 	imes 650$Step $1$: Simplify the fraction $1 \frac{1}{23}$ as $\frac{24}{23}$.Step $2$: Calculate the right-hand side:$\frac{1}{6} 	imes \frac{92}{100} 	imes \frac{24}{23} 	imes 650$$= (\frac{1}{6} 	imes 24) 	imes (\frac{92}{23}) 	imes (\frac{650}{100})$$= 4 	imes 4 	imes 6.5$$= 16 	imes 6.5 = 104$Step $3$: Solve for $x$:$85 + x = 104$$x = 104 - 85$$x = 19$

$\frac{1}{6}$ of $(92 \%)$ of $1 \frac{1}{23}$ of $(650) = 85 + ?$

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