sqrt{10} times sqrt{15} = ? | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To solve $\sqrt{10} 	imes \sqrt{15}$,we use the property $\sqrt{a} 	imes \sqrt{b} = \sqrt{a 	imes b}$.$\sqrt{10} 	imes \sqrt{15} = \sqrt{10

Vedclass · Accepted Answer

$5 \sqrt{6}$

Vedclass · Answer

(A) To solve $\sqrt{10} 	imes \sqrt{15}$,we use the property $\sqrt{a} 	imes \sqrt{b} = \sqrt{a 	imes b}$.$\sqrt{10} 	imes \sqrt{15} = \sqrt{10 	imes 15} = \sqrt{150}$.Now,factorize $150$ to simplify the square root:$150 = 25 	imes 6$.Therefore,$\sqrt{150} = \sqrt{25 	imes 6} = \sqrt{25} 	imes \sqrt{6}$.Since $\sqrt{25} = 5$,the expression simplifies to $5 \sqrt{6}$.

$\sqrt{10} \times \sqrt{15} = ?$

Similar Questions

The smallest number to be added to $680621$ to make the sum a perfect square is

$\sqrt{\frac{4}{3}}-\sqrt{\frac{3}{4}}=?$

$\sqrt{1.5625} = ?$

If $x = (7 - 4\sqrt{3})$,then the value of $\left(x + \frac{1}{x}\right)$ is

The value of $\frac{1+\sqrt{0.04}}{1-\sqrt{0.1}}$ is nearly equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module