[(5 sqrt{7}+sqrt{7}) times (4 sqrt{7}+8 sqrt{ | vedclass

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Question

(A) Given expression: $[(5 \sqrt{7} + \sqrt{7}) 	imes (4 \sqrt{7} + 8 \sqrt{7})] - (19)^{2}$First,simplify the terms inside the parentheses:$(5 \sqrt

Vedclass · Accepted Answer

$143$

Vedclass · Answer

(A) Given expression: $[(5 \sqrt{7} + \sqrt{7}) 	imes (4 \sqrt{7} + 8 \sqrt{7})] - (19)^{2}$First,simplify the terms inside the parentheses:$(5 \sqrt{7} + \sqrt{7}) = 6 \sqrt{7}$$(4 \sqrt{7} + 8 \sqrt{7}) = 12 \sqrt{7}$Now,multiply these results:$(6 \sqrt{7}) 	imes (12 \sqrt{7}) = (6 	imes 12) 	imes (\sqrt{7} 	imes \sqrt{7}) = 72 	imes 7 = 504$Next,calculate the square of $19$:$(19)^{2} = 361$Finally,subtract the values:$504 - 361 = 143$

$[(5 \sqrt{7}+\sqrt{7}) \times (4 \sqrt{7}+8 \sqrt{7})]-(19)^{2} = ?$

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