$(x)^{3} = 4913$. Find the value of $x$.

$348 \div 29 \times 15 + 156 = (?)^{3} + 120$

What is the smallest number by which $5600$ must be divided to make it a perfect cube?

The sum of the square of the first number and the cube of the second number is $568$. Also,the square of the second number is $15$ less than the square of $8$. What is the value of $\frac{3}{5}$ of the first number? (Assuming both numbers are positive)

The smallest five-digit number which is a perfect cube is

Find the cube root of $15.625$. (in $.5$)