sqrt{5^{2} times 14 - 6 times 7 + (4)^{?}} = | vedclass

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(D) Given the equation: $\sqrt{5^{2} 	imes 14 - 6 	imes 7 + (4)^{x}} = 18$Squaring both sides,we get: $5^{2} 	imes 14 - 6 	imes 7 + (4)^{x} = 18^{

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$2$

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(D) Given the equation: $\sqrt{5^{2} 	imes 14 - 6 	imes 7 + (4)^{x}} = 18$Squaring both sides,we get: $5^{2} 	imes 14 - 6 	imes 7 + (4)^{x} = 18^{2}$Calculate the values: $25 	imes 14 - 42 + (4)^{x} = 324$$350 - 42 + (4)^{x} = 324$$308 + (4)^{x} = 324$$(4)^{x} = 324 - 308$$(4)^{x} = 16$Since $16 = 4^{2}$,we have $(4)^{x} = 4^{2}$Therefore,$x = 2$.

$\sqrt{5^{2} \times 14 - 6 \times 7 + (4)^{?}} = 18$

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