4, 9, 25, 49, 121, ? | vedclass

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Question

(B) The given series consists of the squares of consecutive prime numbers.$2^{2} = 4$$3^{2} = 9$$5^{2} = 25$$7^{2} = 49$$11^{2} = 121$The next prime n

Vedclass · Accepted Answer

$169$

Vedclass · Answer

(B) The given series consists of the squares of consecutive prime numbers.$2^{2} = 4$$3^{2} = 9$$5^{2} = 25$$7^{2} = 49$$11^{2} = 121$The next prime number after $11$ is $13$.Therefore,the next term is $13^{2} = 169$.

$4, 9, 25, 49, 121, ?$

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